(18a^2-6a+16)/(3a-1)

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Solution for (18a^2-6a+16)/(3a-1) equation: 


D( a )

3*a-1 = 0

3*a-1 = 0

3*a-1 = 0

3*a-1 = 0 // + 1

3*a = 1 // : 3

a = 1/3

a in (-oo:1/3) U (1/3:+oo)

(18*a^2-(6*a)+16)/(3*a-1) = 0

(18*a^2-6*a+16)/(3*a-1) = 0

18*a^2-6*a+16 = 0

2*(9*a^2-3*a+8) = 0

9*a^2-3*a+8 = 0

DELTA = (-3)^2-(4*8*9)

DELTA = -279

DELTA < 0

2 = 0

2/(3*a-1) = 0

a belongs to the empty set

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